A function that evaluates hours. For specific details, see this function's usage.
HOURS ( [ datetime-expression, ] datetime-expression )
HOURS ( datetime-expression, integer-expression )
datetime-expression A date and time.
integer-expression The number of hours to be added to the datetime-expression. If integer-expression is negative, the appropriate number of hours is subtracted from the datetime. If you supply an integer expression, the datetime-expression must be explicitly cast as a DATETIME data type.
For information about casting data types, see CAST function [Data type conversion].
The behavior of this function can vary depending on what you supply:
0000-02-29 is not meant to imply an actual date; it is the date used by the date algorithm.
SQL/2003 Vendor extension.
The following statements return the value 4, signifying that the second timestamp is four hours after the first. It is recommended that you use the second example (DATEDIFF).
SELECT HOURS( '1999-07-13 06:07:12', '1999-07-13 10:07:12' ); SELECT DATEDIFF( hour, '1999-07-13 06:07:12', '1999-07-13 10:07:12' );
The following statement returns the value 17517342.
SELECT HOURS( '1998-07-13 06:07:12' );
The following statements return the datetime 1999-05-13 02:05:07.000. It is recommended that you use the second example (DATEADD).
SELECT HOURS( CAST( '1999-05-12 21:05:07' AS DATETIME ), 5 ); SELECT DATEADD( hour, 5, '1999-05-12 21:05:07' );
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